一类二维Moran测度谱性
首发时间:2019-11-07
摘要:假设~$R_{k}=\begin{pmatrix}a_{k} &0\\0&b_{k}\end{pmatrix}$ 为正整数扩张矩阵, $D_{k}=\{0,1,\cdots,q_{k}-1\}(\tau,\tau')^{t}$ 为平面数字集, 其中~$\tau,\;\tau',\;q_k$ 为正整数且有 $q_k>1$.本文研究由 $\{R_{k}\}_{k=1}^\infty$~和~$\{D_{k}\}_{k=1}^\infty$ 所生成的~$Moran$ 测度\begin{align*}\mu_{\{R_k\},\{D_k\}}:=\delta_{R_1^{-1}D_1}\ast\delta_{(R_1R_2)^{-1}D_2}\ast\cdots\ast\delta_{(R_1 R_2\cdots R_n)^{-1}D_k}\ast\cdots\end{align*}的谱性, 我们证明: $(i)$\;如果~$q_{k}\tau \mid a_{k}\;( k \in {\mathbb{Z}}^{+})$~或~$q_{k}\tau' \mid b_{k}\;(k \in {\mathbb{Z}}^{+})$ ,~ 则~$\mu_{\{R_{k}\},\{D_{k}\}}$~是谱测度;$(ii)$\;如果~$\gcd(\tau\tau', q_{k})=1, q_{k} \mid \frac{a_{k}b_{k}\tau\tau'}{gcd(a_{k}\tau',b_{k}\tau)},\; l=\lim \sup_{k\rightarrow\infty}q_{k}(\frac{\tau}{a_{k}}+\frac{\tau'}{b_k})<1 $ ,~ 则~$\mu_{\{R_k\},\{D_k\}}$~是谱测度.
关键词: Moran 测度; 谱测度; 谱
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Spectrality of certain Moran measures in two-dimension
Abstract:Let $R_k=\begin{pmatrix}a_k &0\\0&b_k\end{pmatrix}$ be an expanding positive integer matrix, and let $D_{k}=$ $\{0,1,\cdots,q_{k}-1\}(\tau, \tau')^t$ be a digit set, where $\tau,\; \tau',\; q_k $ are positive integers, and $q_k>1$.In this paper, we study the spectrality of the Moran measure $\mu_{\{R_k\}\{D_k\}}$ generated by$$\mu_{\{R_k\}\{D_k\}}:=\delta_{R_1^{-1}D_1}\ast\delta_{(R_2R_1)^{-1}D_2}\ast\cdots\ast\delta_{(R_k\cdots R_2R_1)^{-1}D_k}\ast\cdots.$$We proved that if~$q_{k}\tau \mid a_{k}\;( k \in {\mathbb{Z}}^{+})$~or ~$q_{k}\tau' \mid b_{k}\;(k \in {\mathbb{Z}}^{+})$, then $\mu_{\{R_k\}\{D_k\}}$ is spectral measure, and that if ~$\gcd(\tau \tau',q_{k})=1,q_{k} \mid \frac{a_{k}b_{k}\tau \tau'}{\gcd(a_{k}\tau',b_{k}\tau)},\;l=\lim \sup_{k\rightarrow\infty}q_{k}(\frac{\tau}{a_{k}}+\frac{\tau'}{b_{k}})<1$, then $\mu_{\{R_k\}\{D_k\}}$ is spectral measure.
Keywords: Moran measure Spectral measure Spectra
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一类二维Moran测度谱性
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